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Copy pathmath_utils.py
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217 lines (181 loc) · 5.91 KB
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def _fix_fracs(string):
substrs = string.split("\\frac")
new_str = substrs[0]
if len(substrs) > 1:
substrs = substrs[1:]
for substr in substrs:
new_str += "\\frac"
if substr[0] == "{":
new_str += substr
else:
try:
assert len(substr) >= 2
except:
return string
a = substr[0]
b = substr[1]
if b != "{":
if len(substr) > 2:
post_substr = substr[2:]
new_str += "{" + a + "}{" + b + "}" + post_substr
else:
new_str += "{" + a + "}{" + b + "}"
else:
if len(substr) > 2:
post_substr = substr[2:]
new_str += "{" + a + "}" + b + post_substr
else:
new_str += "{" + a + "}" + b
string = new_str
return string
def _fix_a_slash_b(string):
if len(string.split("/")) != 2:
return string
a = string.split("/")[0]
b = string.split("/")[1]
try:
a = int(a)
b = int(b)
assert string == "{}/{}".format(a, b)
new_string = "\\frac{" + str(a) + "}{" + str(b) + "}"
return new_string
except:
return string
def _remove_right_units(string):
# "\\text{ " only ever occurs (at least in the val set) when describing units
if "\\text{ " in string:
splits = string.split("\\text{ ")
assert len(splits) == 2
return splits[0]
else:
return string
def _fix_sqrt(string):
if "\\sqrt" not in string:
return string
splits = string.split("\\sqrt")
new_string = splits[0]
for split in splits[1:]:
if split[0] != "{":
a = split[0]
new_substr = "\\sqrt{" + a + "}" + split[1:]
else:
new_substr = "\\sqrt" + split
new_string += new_substr
return new_string
def _strip_string(string):
# linebreaks
string = string.replace("\n", "")
# print(string)
# remove inverse spaces
string = string.replace("\\!", "")
# print(string)
# replace \\ with \
string = string.replace("\\\\", "\\")
# print(string)
# replace tfrac and dfrac with frac
string = string.replace("tfrac", "frac")
string = string.replace("dfrac", "frac")
# print(string)
# remove \left and \right
string = string.replace("\\left", "")
string = string.replace("\\right", "")
# print(string)
# Remove circ (degrees)
string = string.replace("^{\\circ}", "")
string = string.replace("^\\circ", "")
# remove dollar signs
string = string.replace("\\$", "")
# remove units (on the right)
string = _remove_right_units(string)
# remove percentage
string = string.replace("\\%", "")
string = string.replace(r"\%", "")
# " 0." equivalent to " ." and "{0." equivalent to "{." Alternatively, add "0" if "." is the start of the string
string = string.replace(" .", " 0.")
string = string.replace("{.", "{0.")
# if empty, return empty string
if len(string) == 0:
return string
if string[0] == ".":
string = "0" + string
# to consider: get rid of e.g. "k = " or "q = " at beginning
if len(string.split("=")) == 2:
if len(string.split("=")[0]) <= 2:
string = string.split("=")[1]
# fix sqrt3 --> sqrt{3}
string = _fix_sqrt(string)
# remove spaces
string = string.replace(" ", "")
# \frac1b or \frac12 --> \frac{1}{b} and \frac{1}{2}, etc. Even works with \frac1{72} (but not \frac{72}1). Also does a/b --> \\frac{a}{b}
string = _fix_fracs(string)
# manually change 0.5 --> \frac{1}{2}
if string == "0.5":
string = "\\frac{1}{2}"
# NOTE: X/Y changed to \frac{X}{Y} in dataset, but in simple cases fix in case the model output is X/Y
string = _fix_a_slash_b(string)
return string
def is_equiv(str1, str2, verbose=False):
if str1 is None and str2 is None:
print("WARNING: Both None")
return True
if str1 is None or str2 is None:
return False
try:
ss1 = _strip_string(str1)
ss2 = _strip_string(str2)
if verbose:
print(ss1, ss2)
return ss1 == ss2
except:
return str1 == str2
def remove_boxed(s):
try:
# Try the standard \boxed{...} pattern first
left = "\\boxed{"
if s.startswith(left) and s.endswith("}"):
return s[len(left) : -1]
# If that fails, try plain \boxed without braces
left_alt = "\\boxed"
if s.startswith(left_alt):
return s[len(left_alt) :].strip()
# Otherwise, return None
return None
except Exception:
return None
def last_boxed_only_string(string):
idx = string.rfind("\\boxed")
if idx < 0:
idx = string.rfind("\\fbox")
if idx < 0:
return None
i = idx
right_brace_idx = None
num_left_braces_open = 0
while i < len(string):
if string[i] == "{":
num_left_braces_open += 1
if string[i] == "}":
num_left_braces_open -= 1
if num_left_braces_open == 0:
right_brace_idx = i
break
i += 1
if right_brace_idx == None:
retval = None
# check for $ sign
# there are two examples in MATH dataset where the answer
# is formatted as $\\boxed 2$
# instead of as $\\boxed{2}$
dollar_idx = None
i = idx
while i < len(string):
if string[i] == "$":
dollar_idx = i
i += 1
if dollar_idx == None:
retval = None
else:
retval = string[idx:dollar_idx] # don't include dollar sign
else:
retval = string[idx : right_brace_idx + 1]
return retval